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CASHCAT Trader Turns $86 Into $1.6M With 19,061× Memecoin Bet

The 19,061× return looks like a masterclass until you notice the entry: $86, the kind of position size that survives because losing it means nothing.

Wallet 0xeee2 turned $86 into roughly $1.6 million by trading the memecoin $CASHCAT, a 19,061× return on the position.

The trader spent $86 to buy 17.5 million $CASHCAT, then sold 3.6 million of the tokens for about $390,500. The remaining 13.8 million $CASHCAT are still held, valued at roughly $1.24 million. Combined, the position is worth about $1.6 million against an $86 cost basis.

On-chain records trace the holdings to wallets 0xeee29d1a6fa5873065ad8789c6e15231b48318a0 and 0x32c34a18cc5fd58c0ece1e472e9bf95de8906a8a.

Frequently asked questions

  1. How did the trader turn $86 into $1.6M?

    The wallet spent $86 to buy 17.5 million $CASHCAT, sold 3.6 million for about $390,500, and still holds the remaining 13.8 million, worth roughly $1.24 million.

  2. What is $CASHCAT?

    $CASHCAT is a memecoin token. The seed does not name the protocol or chain it runs on, only that the trader's wallet bought and sold it for the 19,061× return.

  3. Where are the trader's wallets recorded?

    On-chain records show holdings at 0xeee29d1a6fa5873065ad8789c6e15231b48318a0 and 0x32c34a18cc5fd58c0ece1e472e9bf95de8906a8a.

  4. What is the unrealized portion of the trade?

    Of the roughly $1.6 million total, about $390,500 was realized through the partial sale. The remaining $1.24 million is paper value based on the still-held 13.8 million $CASHCAT.

  5. Is a 19,061× return reproducible?

    The seed only documents one wallet's outcome. Returns at this magnitude on memecoins are rare; most traders in similar positions exit with the loss of the entry-cost amount.

Source attribution
Aggregated from Lookonchain · Verified · Last refreshed 45m ago
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